GTA Equation §

Created Time: February 10, 2022 12:53 PM Database: Inbox Database Last Edited Time: March 11, 2022 11:32 PM Status: Archived

(A-BC)=X

A=X+BC

BC=X+A

B= $\frac{X+A}{C}$

(Ax(B+1)/2xC)+3 % 10 = X

{ $\frac{(1+BC)x(B+1)}{2xC}$+3 % 10 = X

{ $\frac{B+1+B^{2}C+BC}{2C}$+3 % 10 = X

A+BxC=X

$(A\times \frac{(B+1)}{2C}{)}^2$=X

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B= $\pi (3A{)}^2$

B= $3\pi A^2$

C= $2\pi A^2$

(A+ $3\pi A^2$+ $2\pi A^2$)=X

A+ $5\pi A^2$=X

A(1+5 $\pi A)$=X